Math : Trigonometry |
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Hide all answers View all answers Print Try the Quiz 1. ![]() a / b c / b b / a a / c c / a Answer: c / b The sine of an angle is defined as Opposite Side / Hypotenuse. Now for angle C, the opposite side is c and the hypotenuse is b. Hence the correct answer is c/b. 2. From the figure given on the right, the value of sin A + cos A is ![]() (b + c)/a (a + b)/c (a - b)/b (a + b + c)/b (a + c)/b Answer: (a + c)/b We know sin A = a/b, and cos A = c/b. Hence sin A + cos A = (a + c)/b. 3. ![]() b / a c / a c / b b / c a / b Answer: a / b We know that cos of any angle = Base/Hypotenuse. Now for the angle C, the base is a and hypotenuse is b. So cos C = a/b.
4. For the figure given on the right, which of the following relationships is true : ![]() sin A = a / c cos A = b / c tan A = a / b sec A = b / a cot A = c / a Answer: cot A = c / a By definition, cot A = 1 / tan A = c / a. 5. ![]() b/a + a/b a/b + c/b 2b/a 2a/b b/c + c/a Answer: 2a/b The value of cos C = a/b. Similarly the value of sin A = a/b. Hence cos C + sin A = 2a/b. 6. Which of the following relationships is true: sin A / cosec A = cot A sin A / cos A = tan A cos A / sin A = sec A cosec A / sin A = cos A tan A / cot A = sin A Answer: sin A / cos A = tan A The expression sin A / cos A = tan A is a useful one to remember in trigonometry. 7. tan A / sin A = cosec A sin A sec A cos A 1 / sin A Answer: sec A tan A = sin A / cos A. Therefore tan A / sin A = 1 / cos A = sec A. 8. (sin A / tan A) + cos A = 2 cos A 2 sec A sec A 2 cosec A 1 + cos A Answer: 2 cos A We know tan A = sin A / cos A. Therefore (sin A / tan A) + cos A = cos A + cos A = 2 cos A. 9. cot A tan A = 1 sin A cos A sin A cos A 1/(sin A cos A) Answer: 1 cot A = 1 / tan A. Hence cot A tan A = 1. Alternatively cot A = cos A/sin A and tan A= sin A/cos A. So cot A tan A = (cos A/sin A) (sin A/cos A) = 1. 10. ![]() (a + b)/c a/(b + c) (b + c)/a b/(a + c) (a + c)/b Answer: (b + c)/a We know cosec A = b/a and cot A = c/a. Hence cosec A + cot A = (b + c)/a. 11. Which of the following relationships is true: sin A cot A = 1 sin A + cosec A = 1 sec A - cos A = 1 cos A sec A = 1 sec A cot A = 1 Answer: cos A sec A = 1 By definition, sec A = 1 / cos A. So cos A sec A = 1 is true. 12. ![]() a/b + c/b 1 b/a + c/b (a/b + c/b)2 (b/a + c/b)2 Answer: 1 This question is a bit tricky. We know sin A = a/b and cos A = c/b. So sin2 A + cos2 A = (a2 + c2) / b2. By Pythagoras Theorem, a2 + c2 = b2 for a right-angled triangle. Hence sin2 A + cos2 A = 1, which is a famous identity. 13. ![]() (a + c)/b (c + b)/a a/c + c/b (a + b)/c c/a + b/c Answer: (a + b)/c cot C is Base/Opposite Side and cosec C is Hypotenuse/Opposite Side. From these definitions, the values of cot C and cosec C are given by a/c and b/c respectively. Hence the answer is (a + b)/c. 14. cosec A / sec A = tan A sin A cos A sin A + cos A cot A Answer: cot A By definition, cosec A = 1 / sin A and sec A = 1 / cos A. So cosec A / sec A = cos A / sin A = cot A. 15. For the figure given on the right, the value of cot A is ![]() sin A / cos A cos C / sin C tan C a / c c / b Answer: tan C The value of cot A is c/a. Similarly the value of tan C is c/a. Hence cot A = tan C.
Try the Quiz : Practice Exercise for Trigonometry Module 1 : Trigonometric Functions |