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| From: ushenoy | Reply 1 of 9 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 49 |
1
The Earth completes one revolution (360°) around the Sun in about 365
days.
So, rate of revolution = 360°/365 days = 1° per day
(approx.)
Posted at: Fri Nov 27 15:51:37 2009 (GMT)
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| From: ushenoy | Reply 2 of 9 | Reply | View replies (5)
|
| Subject: Contributed Answer/Explanation to Q. 6 |
3
The eccentricity of an ellipse is a measure of how nearly circular the
ellipse is, and is found by the following formula:
<blockquote>
eccentricity = c/a
</blockquote>
<blockquote>
where
</blockquote>
<blockquote>
c = distance from the center C to focus F, and
</blockquote>
<blockquote>
a= distance from the center C to vertex V.<br />
</blockquote>
<blockquote>
In the given diagram, visualize a horizontal line through F1 and
F2. Then, we have,
</blockquote>
<blockquote>
V
F &nb
sp; C
</blockquote>
<blockquote>
<---- c ----->
</blockquote>
<blockquote>
<------ a -------->
</blockquote>
<blockquote>
Since c > 0.5a and c < a, the approximate eccentricity is c/a
= 0.7 <br />
</blockquote>
Posted at: Fri Nov 27 16:20:01 2009 (GMT)
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| From: ushenoy | Reply 3 of 9 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 6 |
3
The eccentricity of an ellipse is a measure of how nearly circular the
ellipse is, and is found by the following formula: eccentricity = c/awherec
= distance from the center C to focus F, anda= distance from the center C to
vertex V.In the given diagram, visualize a horizontal line through F1 and
F2. Then, we have,
<blockquote>
V
F &nb
sp; C
</blockquote>
<blockquote>
<---- c ----->
</blockquote>
<blockquote>
<------ a -------->
</blockquote>
<blockquote>
Since c > 0.5a and c < a, the approximate eccentricity is c/a
= 0.7 <br />
</blockquote>
Posted at: Fri Nov 27 16:23:11 2009 (GMT)
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| From: ushenoy | Reply 4 of 9 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 6 |
3
<p>
The eccentricity of an ellipse is a measure of how nearly circular the
ellipse is, and is found by the following formula:
</p>
<p>
eccentricity = c/a, where
</p>
<p>
c = distance from the center C to focus F, and
</p>
<p>
a= distance from the center C to vertex V.
</p>
<p>
In the given diagram, visualize a horizontal line through F1 and F2.
Then, we have,
</p>
<blockquote>
V
F &nb
sp; C
</blockquote>
<blockquote>
<---- c ----->
</blockquote>
<blockquote>
<------ a -------->
</blockquote>
<blockquote>
Since c > 0.5a and c < a, the approximate eccentricity is c/a
= 0.7 <br />
</blockquote>
Posted at: Fri Nov 27 16:24:10 2009 (GMT)
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| From: ushenoy | Reply 5 of 9 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 6 |
3
The eccentricity of an ellipse is a measure of how nearly circular the
ellipse is, and is found by the following formula:
eccentricity = c/a, where
c = distance from the center C to focus F, and
a= distance from the center C to vertex V.
In the given diagram, visualize a horizontal line through F1 and F2.
Then, we have,V
F &nb
sp; C<---- c -----><------ a -------->Since c >
0.5a and c < a, the approximate eccentricity is c/a = 0.7
Posted at: Fri Nov 27 16:25:05 2009 (GMT)
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| From: ushenoy | Reply 6 of 9 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 6 |
3
The eccentricity of an ellipse is a measure of how nearly circular the
ellipse is, and is found by the following formula:
Eccentricity = c/a, where
c = distance from the center C to focus F, and
a= distance from the center C to vertex V.
In the given diagram, visualize a horizontal line through F1 and F2.
Then, we have,
V
F &nb
sp; C
<---- c ----->
<------ a -------->
Since c > 0.5a and c < a, the approximate eccentricity is c/a =
0.7
Posted at: Fri Nov 27 16:26:03 2009 (GMT)
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| From: ushenoy | Reply 7 of 9 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 6 |
3
The eccentricity of an ellipse is a measure of how nearly circular the
ellipse is, and is found by the following formula:
Eccentricity = c/a, where
c = distance from the center C to focus F, and
a = distance from the center C to vertex V.
In the given diagram, visualize a horizontal line through F1 and F2.
Then, we have,
V
F &nb
sp; C
<---- c ----->
<------ a -------->
Since c > 0.5a and c < a, the approximate eccentricity is c/a =
0.7
Posted at: Fri Nov 27 16:26:45 2009 (GMT)
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| From: azmol218 | Reply 8 of 9 | Reply | View replies (1)
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| Subject: Contributed Answer/Explanation to Q. 9 |
hkdjfhba iurjg:FDGDAJHERGnkj jhaHKQLTaj
Posted at: Wed May 13 02:33:52 2015 (GMT)
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| From: azmol218 | Reply 9 of 9 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 9 |
The Foucault pendulum appears to spin in its axis by rotate on the Floor.
Posted at: Wed May 13 02:35:19 2015 (GMT)
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